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(CH(3))(4)N^(+) is neither an electroph...

`(CH_(3))_(4)N^(+)` is neither an electrophile , nor a nucleophile because it

A

does not have electron pair for donation as well as cannot attract electron pair

B

neither has electron pair available for donation nor can accommodate electron since all shells of N are fully occupied

C

can act as Lewise acid and base

D

none of these

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The correct Answer is:
To determine why the compound \((CH_3)_4N^+\) is neither an electrophile nor a nucleophile, we can analyze its structure and electronic configuration step by step. ### Step 1: Identify the Structure of the Compound The compound \((CH_3)_4N^+\) consists of a nitrogen atom bonded to four methyl groups (CH₃). This means that nitrogen is surrounded by four carbon atoms. **Hint:** Look at the number of substituents attached to the central atom (nitrogen in this case). ### Step 2: Determine the Hybridization and Bonding of Nitrogen In \((CH_3)_4N^+\), nitrogen forms four sigma bonds with the four methyl groups. This means nitrogen is sp³ hybridized. **Hint:** Recall that sp³ hybridization involves four bonds, leading to a tetrahedral geometry. ### Step 3: Analyze the Charge on the Nitrogen Atom The nitrogen atom in this compound has four bonds and carries a positive charge (\(N^+\)). This indicates that nitrogen has used all its valence electrons to form bonds, resulting in a complete octet. **Hint:** Remember that a positive charge indicates a deficiency of electrons compared to a neutral atom. ### Step 4: Evaluate Nucleophilicity A nucleophile is typically characterized by the presence of a lone pair of electrons or a negative charge, allowing it to donate electrons. In \((CH_3)_4N^+\), nitrogen does not have a lone pair because all its valence electrons are involved in bonding. Therefore, it cannot act as a nucleophile. **Hint:** Nucleophiles need either a lone pair or a negative charge to donate electrons. ### Step 5: Evaluate Electrophilicity An electrophile is an electron-deficient species that can accept electrons. For a species to act as an electrophile, it usually has an incomplete octet or a positive charge. However, in this case, nitrogen has a complete octet (8 electrons from 4 bonds), meaning it is not electron-deficient. Therefore, it cannot act as an electrophile. **Hint:** Electrophiles often have incomplete octets or are positively charged but need to be electron-deficient. ### Conclusion Since \((CH_3)_4N^+\) has no lone pairs and its octet is complete, it is neither a nucleophile nor an electrophile. ### Final Answer \((CH_3)_4N^+\) is neither an electrophile nor a nucleophile because it has no lone pair for donation and its octet is fully occupied.

To determine why the compound \((CH_3)_4N^+\) is neither an electrophile nor a nucleophile, we can analyze its structure and electronic configuration step by step. ### Step 1: Identify the Structure of the Compound The compound \((CH_3)_4N^+\) consists of a nitrogen atom bonded to four methyl groups (CH₃). This means that nitrogen is surrounded by four carbon atoms. **Hint:** Look at the number of substituents attached to the central atom (nitrogen in this case). ### Step 2: Determine the Hybridization and Bonding of Nitrogen ...
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Knowledge Check

  • (CH_(3))_(4)N^(+) is neither an electrophile, nor nucleophilic because it

    A
    Does not have electron pair for donation as well as can not attract electron pair
    B
    neither has electron pair avaible for donation nor can accommodate electron since all shells of N are fully occupied
    C
    can act as Lewis acid and base
    D
    None of these
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    A
    S is an electron deficient element
    B
    O is highly electronegative
    C
    S is larger in size
    D
    All of the above
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    A
    `CH_(3)-N^(+)equivC^(-)`
    B
    `CH_(2)=O`
    C
    `H_(3)N :`
    D
    `BeCl_(2)`
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