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The potential energy of a particle of ma...

The potential energy of a particle of mass 1 kg moving along x-axis given by `U(x)=[(x^(2))/(2)-x]J`. If total mechanical speed (in m/s):-

A

`sqrt(5)`

B

`sqrt(7)`

C

`sqrt(3)`

D

None

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A
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Knowledge Check

  • The potential energy of a 1kg particle free to move along the x-axis is given by V(x)=(x^(4)/4-x^(2)/2)J The total mechanical energy of the particle is 2J then the maximum speed (in m//s) is

    A
    `3/sqrt(2)`
    B
    `3sqrt(2)`
    C
    `9/2`
    D
    `2`

  • The potential energy of particle of mass 1kg moving along the x-axis is given by U(x) = 16(x^(2) - 2x) J, where x is in meter. Its speed at x=1 m is 2 m//s . Then,

    A
    the motion of the particle is uniformly accelerated
    B
    the motion of the particle is periodic but not simple harmonic.
    C
    the motion of the particle is simple harmonic having equilibrium position at x=1m
    D
    kinetic energy of the particle is conserved

  • The potential energy of a 1 kg particle free to move along the x-axis is given by V(x) ((x^4)/4 - (x^2)/2)J The total mechanical energy of the particle is 2 J. Then, the maximum speed (in m/s) is

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