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Find the distance of the point on y=x^4+...

Find the distance of the point on `y=x^4+3x^2+2x` which is nearest to the line `y=2x-1`

A

`(2)/(sqrt(5))`

B

`sqrt(5)`

C

`(1)/(sqrt(5))`

D

`5 sqrt(5)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The point on the ellipse x^(2)+2y^(2)=6 which is nearest to the line x-y=7 is

    A
    `((sqrt6)/(sqrt5),(sqrt3)/(sqrt5))`
    B
    `(2,-1)`
    C
    `(-2, 1)`
    D
    `(-2, -1)`

  • The point on the ellipse x^(2)+2y^(2)=6 which is nearest to the line x-y=7 is

    A
    `((sqrt(6))/(sqrt(5)),(sqrt(3))/(sqrt(5)))`
    B
    `(2,-1)`
    C
    `(-2,1)`
    D
    `(-2,-1)`

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