On electrolysis of dilute sulphuric acid using platinum electrodes, the product obtained at the anode will be

Options

A. hydrogen
B. oxygen is more reactive than nitrogen.
C. hydrogen sulphide
D. sulphur dioxide

Explanation

To solve the question regarding the product obtained at the anode during the electrolysis of dilute sulfuric acid using platinum electrodes, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Electrolysis**:
- Electrolysis involves passing an electric current through an electrolyte (in this case, dilute sulfuric acid, H₂SO₄) to induce a chemical reaction.

2. **Identifying the Electrolyte**:
- Dilute sulfuric acid dissociates in water to produce hydrogen ions (H⁺) and sulfate ions (SO₄²⁻):
\[ \text{H}_2\text{SO}_4 \rightarrow 2\text{H}^+ + \text{SO}_4^{2-} \]

3. **Determining the Electrodes**:
- In electrolysis, the anode is the positive electrode where oxidation occurs, and the cathode is the negative electrode where reduction occurs.

4. **Identifying Ions at the Anode**:
- At the anode, negatively charged ions (anions) are attracted. In dilute sulfuric acid, the relevant anions are hydroxide ions (OH⁻) from water and sulfate ions (SO₄²⁻).

5. **Comparing Electrode Potentials**:
- The discharge of ions at the anode depends on their standard electrode potentials. The hydroxide ion (OH⁻) has a lower discharge potential compared to the sulfate ion (SO₄²⁻), meaning it is preferentially discharged.

6. **Reaction at the Anode**:
- When hydroxide ions are discharged, they undergo oxidation to form oxygen gas (O₂):
\[ 4\text{OH}^- \rightarrow 2\text{H}_2\text{O} + \text{O}_2 + 4e^- \]
- This indicates that oxygen gas is produced at the anode.

7. **Conclusion**:
- Therefore, the product obtained at the anode during the electrolysis of dilute sulfuric acid using platinum electrodes is **oxygen gas (O₂)**.

### Final Answer:
The product obtained at the anode will be **oxygen gas (O₂)**.

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