Home
Class 12
PHYSICS
A bird in air looks at a fish vertically...

A bird in air looks at a fish vertically below it and inside water. `h_(1)` is the height of the bird above the surface of water and `h_(2)`, the depth of the fish below the surface of water. If refractive index of water with respect to air be `mu`, then the distance of the fish as observed by the bird is

A

`h_(1)+h_(2)`

B

`h_(1)+(h_(2))/(mu)`

C

`muh_(1)+h_(2)`

D

`muh_(1)+muh_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine the distance of the fish as observed by the bird, taking into account the refractive index of water. ### Step 1: Understand the Setup We have a bird flying in the air at a height \( h_1 \) above the surface of the water and a fish located at a depth \( h_2 \) below the water surface. The refractive index of water with respect to air is given as \( \mu \). ### Step 2: Determine Actual Distance The actual distance between the bird and the fish can be calculated as the sum of the height of the bird above the water and the depth of the fish below the water: \[ \text{Actual Distance} = h_1 + h_2 \] ### Step 3: Calculate Apparent Depth of the Fish When the bird looks down into the water, the fish appears to be at a different depth due to the refraction of light. The apparent depth \( h_{2, \text{apparent}} \) of the fish as seen by the bird can be calculated using the formula: \[ h_{2, \text{apparent}} = \frac{h_2}{\mu} \] This formula indicates that the apparent depth is less than the actual depth because \( \mu \) (the refractive index of water) is greater than 1. ### Step 4: Combine Heights for Apparent Distance The total apparent distance \( D \) that the bird perceives to the fish is the sum of the height of the bird above the water and the apparent depth of the fish: \[ D = h_1 + h_{2, \text{apparent}} = h_1 + \frac{h_2}{\mu} \] ### Step 5: Final Expression Thus, we can express the apparent distance of the fish as observed by the bird: \[ D = h_1 + \frac{h_2}{\mu} \] ### Conclusion The distance of the fish as observed by the bird is given by: \[ D = h_1 + \frac{h_2}{\mu} \]

To solve the problem step by step, we need to determine the distance of the fish as observed by the bird, taking into account the refractive index of water. ### Step 1: Understand the Setup We have a bird flying in the air at a height \( h_1 \) above the surface of the water and a fish located at a depth \( h_2 \) below the water surface. The refractive index of water with respect to air is given as \( \mu \). ### Step 2: Determine Actual Distance The actual distance between the bird and the fish can be calculated as the sum of the height of the bird above the water and the depth of the fish below the water: \[ ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    DISHA PUBLICATION|Exercise Exercise - 1 : Concept Builder (Topicwise)(Topic 5 : Optical Instruments)|5 Videos
  • PHYSICAL WORLD, UNITS AND MEASUREMENTS

    DISHA PUBLICATION|Exercise Exercise - 2 : Concept Applicator|30 Videos
  • SEMICONDUCTOR ELECTRONICS : METERIALS, DEVICES AND SIMPLE CIRCUITS

    DISHA PUBLICATION|Exercise EXERCISE -2: CONCEPT APPLICATOR|25 Videos

Similar Questions

Explore conceptually related problems

Refractive index of water with respect to air is 1.33. What is the refractive index of air with respect to water ?

The refractive index of water witih respect to air is 4/3 . The refractive index of air with respect to water will be:

Knowledge Check

  • If refractive index of water with respect to air is (4)/(3), then refractive index of air with respect to water is

    A
    `4 xx 3 `
    B
    `3/4`
    C
    `sqrt ((4)/(3))`
    D
    `sqrt ((3)/(4))`
  • If refractive index of water with respect to air is then refractive index of air with respect to water is

    A
    `4 xx 3`
    B
    `(3)/(4)`
    C
    `sqrt((4)/(3))`
    D
    `sqrt((3)/(4))`
  • A bird in air looks at fish vertically below it and inside water in a tank. If the distances of the fish as estimated by the bird is hx and that of bird as estimated by the fish is h_(2) , then the refractive index of liquid is :-

    A
    `h_(2)/h_(1)`
    B
    `h_(1)/h_(2)`
    C
    `(h_(1) + h_(2))/(h_(1) - h_(2))`
    D
    `(h_(1) - h_(2))/(h_(1) + h_(2))`
  • Similar Questions

    Explore conceptually related problems

    Refractive index of water with respect to air is 1.33. What is the value of refractive index of air with respect to water?

    A point source is placed at a depth h below the surface of water (refractive index = mu ). The medium above the surface of water is air from water.

    A fish in water (refractive index n ) looks at a bird vertically above in the air. If y is the height of the bird and x is the depth of the fish from the surface, then the distance of the bird as estimated by the fish is

    A bird in air is at a height ‘y’ from the surface of water. A fish is at a depth ‘x’ below the surface of water. The apparent distance of fish from the bird is (The refractive index of water is n )

    A bird is flying 3m above the surface of water. To a fish underwater, the height of the bird from the water surface appears to be