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Given the electric field of a complete a...

Given the electric field of a complete amplitude modulated wave as
` vecE= hati E_C ( 1 + (E_m)/(E_C) cos omega_m t ) cos omega_c t`.
Where the subscript c stands for the carrier wave and m for the modulating signal . The frequencies present in the modulated wave are

A

`omega_c and sqrt( omega_c^(2) + omega_m^(2))`

B

`omega_c , omega_c + omega_m and omega_c - omega_m`

C

`omega_c and omega_m `

D

`omega_c and sqrt( omega_c omega_m)`

Text Solution

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The correct Answer is:
To find the frequencies present in the given amplitude modulated wave, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Electric Field Equation**: The electric field of the amplitude modulated wave is given by: \[ \vec{E} = \hat{i} E_C \left(1 + \frac{E_m}{E_C} \cos(\omega_m t)\right) \cos(\omega_c t) \] Here, \(E_C\) is the amplitude of the carrier wave, \(E_m\) is the amplitude of the modulating signal, \(\omega_c\) is the angular frequency of the carrier wave, and \(\omega_m\) is the angular frequency of the modulating signal. 2. **Identify the Frequencies**: In amplitude modulation, the modulated wave consists of: - The **carrier frequency**: This is represented by \(\omega_c\). - The **upper sideband frequency**: This is given by \(\omega_c + \omega_m\). - The **lower sideband frequency**: This is given by \(\omega_c - \omega_m\). 3. **List the Frequencies Present**: Therefore, the frequencies present in the modulated wave are: - Carrier Frequency: \(\omega_c\) - Upper Sideband Frequency: \(\omega_c + \omega_m\) - Lower Sideband Frequency: \(\omega_c - \omega_m\) 4. **Conclusion**: The three frequencies present in the amplitude modulated wave are: \[ \omega_c, \quad \omega_c + \omega_m, \quad \omega_c - \omega_m \] ### Final Answer: The frequencies present in the modulated wave are: - \(\omega_c\) - \(\omega_c + \omega_m\) - \(\omega_c - \omega_m\)

To find the frequencies present in the given amplitude modulated wave, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Electric Field Equation**: The electric field of the amplitude modulated wave is given by: \[ \vec{E} = \hat{i} E_C \left(1 + \frac{E_m}{E_C} \cos(\omega_m t)\right) \cos(\omega_c t) ...
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Knowledge Check

  • If omega_c and omega_m are angular frequencies of carrier wave and modulating signal respectively, then Band width of amplitude modulated waves is equal to

    A
    `(omega_c+omega_m)/2`
    B
    `2omega_m`
    C
    `2omega_c`
    D
    `(omega_c-omega_m)/2`
  • If A_m and A_c are the amplitudes of modulating signal and carrier wave respectively, then modulation index is given by

    A
    `mu=A_m/A_c`
    B
    `mu=A_c/A_m`
    C
    `mu=A_c^2/A_m`
    D
    `mu=A_m^2/A_c`
  • If E_(c)=10 sin 10^(5) pit and E_(m)=10 sin 400 pi t are carrier and modulating signals respectively , the modulation index is

    A
    0.56
    B
    0.3
    C
    0.5
    D
    0.48
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