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In a solid AB having the NaCl structure,...

In a solid `AB` having the `NaCl` structure, A atom occupies the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

A

`AB_2`

B

`A_2B`

C

`A_4B_3`

D

`A_3B_4`

Text Solution

Verified by Experts

The correct Answer is:
D
No. of atoms (A) on the corners = 8
No. of atoms (A) on the face centres = 6
Removing face centred atoms along one of the axes
means removal of 2A atoms so that
No. of A atoms per unit cell = `8 xx 1/8 + 4 xx 1/2 = 3`
No. of B atoms per unit cell in NaCl type structure = 4
Formula = `A_3B_4`.
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Knowledge Check

  • In a solid AB having the NaCl structure, A atoms occupy the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

    A
    `AB_2`
    B
    `A_2B`
    C
    `A_4B_3`
    D
    `A_3B_4`

  • In a solid 'AB' having the NaCl structure, A atoms occupy the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed then the resultant stoichiometry of the solid is

    A
    `AB_(2)`
    B
    `A_(2)B`
    C
    `A_(4)B_(3)`
    D
    `A_(3)B_(4)`

  • In a solid 'AB' having NaCl structure , 'A' atoms occupy the corners of the cubic unit cell. If cell the face-centred atoms along one of the axes are removed , then the resultant stoichiometry of the solid is

    A
    `AB_2`
    B
    `A_2B`
    C
    `A_4B_3`
    D
    `A_3B_4`