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Two tuning forks when sounded together g...

Two tuning forks when sounded together give 8 beats per second. When tuning fork A is sounded with air column of length 37.5 cm closed at one end, resonance occurs in its fundamental mode. Tuning fork B gives resonance with air column of length 38.5 cm and is closed at one end in its fundamental mode. Find the frequencies of tuning forks.

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To solve the problem step by step, we will follow the reasoning and calculations outlined in the video transcript. ### Step 1: Understanding the Beat Frequency When two tuning forks are sounded together, they produce beats. The number of beats per second is equal to the absolute difference in their frequencies. Here, we are given that the beat frequency is 8 beats per second. Let: - \( F_A \) = frequency of tuning fork A - \( F_B \) = frequency of tuning fork B ...
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Knowledge Check

  • A tuning fork of frequency 440 Hz resonates with a tube closed at one end of length 1.8 cm and diameter 5 cm in fundamental mode. The velocity of sound in air is

    A
    `336ms^(-1)`
    B
    `343ms^(-1)`
    C
    `300ms^(-1)`
    D
    `350ms^(-1)`
  • In a resonance tube experiment, a tuning fork resonates with an air column of length 12 cm and again resonates when it is 38cm long. The end correction will be

    A
    `0.25` cm
    B
    `0.5` cm
    C
    `0.75` cm
    D
    1 cm
  • Two tuning forks n_1 " and "n_2 when sounded together produces 5 beats per second . If the fork n_1 is in resonance with a closed tube of length 8cm and other n_2 is resonance with an open tube of length 16.5cm the frequency n_1 will be

    A
    165Hz
    B
    140Hz
    C
    140Hz
    D
    145Hz
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