Calculate the molar conductance of 0.01M aqueous KCl solution at `25^@C`. The specific conductance of KCl at `25^@C` is `14.114 xx 10^(-2) Sm^(-1)`.

Explanation

Concentration of KCl solution = 0.01M
Specific conductance `(k) = 14.114 xx 10^(-2)Sm^(-1)`
Molar conductance `(Lambda_m) = ?`
`Lambda_, = (k xx 10^(-3))/(M) = (14.114 xx 10^(-2) xx 10^(-3))/(0.01) Sm^(-1) mol^(-1) m^(3)`
`Lambda_m = 14.114 xx 10^(-5) xx 10^2 = 14.114 xx 10^(-3) Sm^2 mol^(-1)`.