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A particle of mass m is moving with a un...

A particle of mass m is moving with a uniform velocity `v_(1)`. It is given an impulse such that its velocity becomes `v_(2)`. The impulse is equal to

A

`m(vecv_(2)-vecv_(1))`

B

`m( vecv_(1)-vecv_(2))`

C

`1.5mxx(vecv_(2)-vecv_(1))`

D

`0.5m(vecv_(2)-vecv_(1))`

Text Solution

Verified by Experts

The correct Answer is:
A
Impulse change in momentum `=m vec v_(2)- m vec_(1)`
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Knowledge Check

  • A particle of mass m_(1) is moving with a velocity v_(1) and another particle of mass m_(2) is moving with a velocity v_(2) . Both of them have the same momentum but their different kinetic energies are E_(1) and E_(2) respectively. If m_(1)gtm_(2) then

    A
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    mv
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    `mv^(2)`
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