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The brown - ring complex compound of iro...

The brown - ring complex compound of iron is formulated as `[Fe(H_2O)_5(NO)]SO_4` . The oxidation state of iron is :

A

l

B

2

C

3

D

O

Text Solution

Verified by Experts

The correct Answer is:
B
(b) Sum of oxidation state ofall atoms in neutral compound is zero. Let the oxidation state of iron in the complex ion `[Fe(H_2,O)_5,(NO)]^(2+) SO_(4)^(2-)` be x, then `x+5 xx 0+0 = +2`
`therefore x = + 2`
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  • The brown - ring complex compound of iron is formulate as [Fe(H_(2)O)_(5)(NO)]SO_(4) . The oxidation state of iron is :

    A
    1
    B
    2
    C
    3
    D
    0

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    A
    1
    B
    2
    C
    3
    D
    0

  • The brown ring complex compound is formulated as [Fe(H_(0)O)_(5)(NO)]SO_(4) the oxidation state of iron is -

    A
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    B
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    D
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