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The ionization energy of lithium is 520 ...

The ionization energy of lithium is 520 kJ `"mol"^(-1)` . Find the amount of energy (in kJ) required to convert 70 mg of lithium atoms in gaseous state into Li+ ions.

Text Solution

Verified by Experts

The correct Answer is:
5.2
70 mg `=70 xx 10^(-7) g = (70 xx 10^(-3))/7 mol = 1 xx 10^(-2)` mol
`therefore` Amount of energy required
`= 1 xx 10^(-2) xx 520 kJ = 5.2 kJ`
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