KEY IDEA
We can calculate the torso speed at any time by finding an area on the torso a(t) graph.
Calculations : We know that the initial torso speed is `v_(0)=0` at time `t_(0)=0` , at the start of the " collision." We want the torso speed `v_(1)` at time `t_(1)=110ms`, which is when the head begins to accelerate.
Combining Eqs. 2-27 and 2-28, we can write
`v_(1)-v_(0)= `( area between acceleration curve and time axis, from `t_(0)` to `t_(1)` ). (2-31)
For convenience, let us separate the area into three regions ( Fig. 2-15b). From 0 to 40 ms, region A has no area :
`"area"_(A)=0`.
From 40 ms to 100 ms, region B has the shape of a triangle, with area
`"area"_(B)= 1/2 (0.060 s) (50 m//s^(2))= 1.5 m//s.`
From 100 ms to 110 ms, region C has the shape of a rectangle, with area
`"area"_(C)= (0.010 s) (50 m//s^(2))= 0.50 m//s`.
Substituting these values and `v_(0)=0` into Eq. 2-31 gives us
`v_(1)-0 = 0+1.5 m//s + 0.50 m//s`,
or `v_(1) = 2.0 m//s = 7.2 km//h`.
Reasoning: When the head is just starting to move forward, the torso already has a speed of 7.2 km/h.
Researchers argue that it is this difference in speeds during the early stage of a rear-end collision that injures the neck. The backward whipping of hte head happens later and could, especially if there is no head restraint, increase the injury.
