Home
Class 11
MATHS
Let A={9,10,11,12,13} and let f: A to N ...

Let A={9,10,11,12,13} and let `f: A to N` be defined by f(n)= the highest prime factor of n. Find the range of f.

Answer

Step by step text solution for Let A={9,10,11,12,13} and let f: A to N be defined by f(n)= the highest prime factor of n. Find the range of f. by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    NCERT TELUGU|Exercise Exercise 2.3|5 Videos
  • PROBABILITY

    NCERT TELUGU|Exercise MISCELLANEOUS EXERCISEON CHAPTER 25|1 Videos
  • SEQUENCES AND SERIES

    NCERT TELUGU|Exercise Miscellaneous Exercise On Chapter 9|31 Videos

Similar Questions

Explore conceptually related problems

If f : N to N is defined as f(x) = 2x+5 , is f onto?

If f:N to N is defined as f(x)=2x+5 , is f onto?

Knowledge Check

  • The function f: N to N defined by f(n) =2n+3 is

    A
    surjective
    B
    injective
    C
    bijective
    D
    neither one-one nor onto
  • Let the function f: R to R be defined by f(x) = 2x + sinx for x in R , then f is

    A
    one - one and onto
    B
    one-one but not on
    C
    onto but not one - on
    D
    neither one - one nor onto
  • Let f : N rarr N be defined by f(x)=x^(2)+x+1, x in N . Then f is

    A
    one-one onto
    B
    many-one onto
    C
    one-one but not onto
    D
    into
  • Similar Questions

    Explore conceptually related problems

    Let A={x in R : x ne 0, -4le xle4} and f:A rarrR is defined by f(x)=(|x|)/(x) for x in A. Then the range of f is

    Let f:[-2, 2] to R be defined by f(x)={x| . Find the global maximum of f(x) and a point of global manimum.

    f: N to R be any function then show that f is continuous on N .

    If N denotes the set of all positive integers and if f : N to N is defined by f(n) = the sum of positive divisors of n then, f(2^(k)3) , where k is a positive integer, is

    If f : N to R is defined by f(1) = -1 and f(n+1)=3f(n)+2 for n gt 1 , then f is