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The position of a particle moving along a straight line is defined by the relation, `x=t^(3)-6t^(2)-15t+40` where x is in meters and t in seconds.The distance travelled by the particle from t=0 to t=2 s is?

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Knowledge Check

  • The displacement of a particle moving in a straight line is described by the relation s=6+12t-2t^(2) . Here s is in metre and t in second. The distance covered by the particle in first 5s is

    A
    `20m`
    B
    `32m`
    C
    `24m`
    D
    `26m`

  • The position of a particle moving on a straight line depends on time t as x=(t+3)sin (2t)

    A
    Its velocity at the initial moment is 6 m/s
    B
    Its acceleration at the initial is `-8 m//s^(2)`
    C
    It has velocity of 3 m/s at `t=(pi)/2` sec
    D
    It has an acceleration of `2 m//s^(2)` at `t=(pi)/4` sec

  • The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

    A
    `2m`
    B
    `3m`
    C
    `4m`
    D
    `6m`

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    Position of a particle moving along a straight line is given by x=2t^(2)+t . Find the velocity at t = 2 sec.

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