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Can the number 6^n, n being a natural nu...

Can the number `6^n`, n being a natural number, end with the digit 5? Give reason.

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Knowledge Check

  • Mean of first n natural numbers is

    A
    `(n(n-1))/2`
    B
    `(n(n+1))/2`
    C
    `((n+1))/(2n`
    D
    `((n+1))/(2`

  • The sum of the cubes of first n natural numbers is -

    A
    `n^(3)`
    B
    `(n(n+1))/(2)`
    C
    `(1)/(6)n(n+1)(2n+1)`
    D
    `[(n(n+1))/(2)]^(2)`

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