Out of 100 students, two sections of 40 and 60 are formed. If you and your friend are among the 100 students, what is the probability that
(a) you both enter the same section?
(b) you both enter the different sections?
Out of 100 students, two sections of 40 and 60 are formed. If you and your friend are among the 100 students, what is the probability that
(a) you both enter the same section?
(b) you both enter the different sections?
(a) you both enter the same section?
(b) you both enter the different sections?
Text Solution
Verified by Experts
The correct Answer is:
(a) `17/33` (b) `16/33`
|
Topper's Solved these Questions
PROBABILITY
NCERT BANGLISH|Exercise MISCELLANEOUS EXERCISEON CHAPTER 21|1 VideosPROBABILITY
NCERT BANGLISH|Exercise MISCELLANEOUS EXERCISEON CHAPTER 22|1 VideosPROBABILITY
NCERT BANGLISH|Exercise MISCELLANEOUS EXERCISEON CHAPTER 19|1 VideosPRINCIPLE OF MATHEMATICAL INDUCTION
NCERT BANGLISH|Exercise EXERCISE - 4.1|24 VideosRELATIONS AND FUNCTIONS
NCERT BANGLISH|Exercise Miscellaneous Exercise on Chapter 2|12 Videos
Similar Questions
Explore conceptually related problems
In a hostel, 60% of the students read Hindi newspaper, 40% read English newspaper and 20% read both Hindi and English newspapers. A student is selected at random. (a) Find the probability that she reads neither Hindi nor English newspapers. (b) If she reads Hindi newspaper, find the probability that she reads English newspaper (c) If she reads English newspaper, find the probability that she reads Hindi newspaper.
Two wires A and B of the same metal have the same across sectional area and have their lengths in the ratio 2:1 What will be the ratio of currents flowing through them respectively, when the same potential difference is applied across each of them?
Knowledge Check
If a current passes through a metal conducting wire of area of cross section A, the drift velocity of free electrons inside the metal is v_d=1/( n e A) , where the amount of electric charge of an electron =e and the number of free electrons per unit volume of the metal=n. The applied electric field on the wire is E=V/l , where a potential difference V exists between two points, l apart, along the length of the wire. IF R is the resistance of the wire between those two points, then the resistivity of its material is rho=(RA)/l .Besides the mobility (mu) of the free electrons inside a wire is defined as their drift velocity for a unit applied electric field. Two copper wires have both lengths and radii in the ratio 1:2 if the ratio between the electric currents flowing through them is also 1:2 , what would be the ratio between the drift velocities of free electrons?
If a current passes through a metal conducting wire of area of cross section A, the drift velocity of free electrons inside the metal is v_d=1/( n e A) , where the amount of electric charge of an electron =e and the number of free electrons per unit volume of the metal=n. The applied electric field on the wire is E=V/l , where a potential difference V exists between two points, l apart, along the length of the wire. IF R is the resistance of the wire between those two points, then the resistivity of its material is rho=(RA)/l .Besides the mobility (mu) of the free electrons inside a wire is defined as their drift velocity for a unit applied electric field. Two copper wires have both lengths and radii in the ratio 1:2 if the ratio between the electric currents flowing through them is also 1:2 , what would be the ratio between the drift velocities of free electrons?
A
`1:1`
B
`1:2`
C
`2:1`
D
`4:1`
A particle of mass m and charge q is accelerated by a potential difference V volt and made to enter a magnetic field region at an angle theta with the field. At the same moment another particle of same mass and charge is projected in the direction of the field from the same point. Magnetic field of induction is B. What would be the speed of second particle so that both particles meet again after a regular interval of time which should be minimum.?
A particle of mass m and charge q is accelerated by a potential difference V volt and made to enter a magnetic field region at an angle theta with the field. At the same moment another particle of same mass and charge is projected in the direction of the field from the same point. Magnetic field of induction is B. What would be the speed of second particle so that both particles meet again after a regular interval of time which should be minimum.?
A
`sqrt((qv)/(m))cos theta`
B
`sqrt((2qv)/(m))cos theta`
C
`sqrt((qv)/(m))sin theta`
D
`sqrt((qv)/(m))cos theta`
Let us take an electrical conductor in which the electrical energy supplied is entirely converted into heat . If , for the conductor , the terminal potential difference = V , the curent through it = I and its resistance = R , then the electrical energy cnsumed in its t is , W=I^(2)t (from Ohm'slaw R=(V)/(I) ) . So , if thr electrical and the heat energies both are expressed in joule , the heat developed in tiem t is H=I^(2)Rt . However , If H is expressed in the conventional unit calorie , then from the law , W = JH , we may write H=(I^(2)Rt)/(J) , where , J = mechanical equivalent of heat =4.2J."cal"^(-1) . The resistance R of a conducting wire depends on its material , its length l and its area of cross section a .The resistivity of the meterial of the conductor is , rho=(RA)/(l) . When more than one heat -producing conductors are kept in series in a circuit , the same current passes through each of them , but as their resistance are f=different in general , the terminal potential differences are also unequal . On the other hand , each conductor has the same terminal potential difference in a parallel combination , however , the curents through them are different . The terminal potential difference and the currents through two conducting wires are both in the ratio 2 : 1 The ratio of the rates of heat evolved in them is
Let us take an electrical conductor in which the electrical energy supplied is entirely converted into heat . If , for the conductor , the terminal potential difference = V , the curent through it = I and its resistance = R , then the electrical energy cnsumed in its t is , W=I^(2)t (from Ohm'slaw R=(V)/(I) ) . So , if thr electrical and the heat energies both are expressed in joule , the heat developed in tiem t is H=I^(2)Rt . However , If H is expressed in the conventional unit calorie , then from the law , W = JH , we may write H=(I^(2)Rt)/(J) , where , J = mechanical equivalent of heat =4.2J."cal"^(-1) . The resistance R of a conducting wire depends on its material , its length l and its area of cross section a .The resistivity of the meterial of the conductor is , rho=(RA)/(l) . When more than one heat -producing conductors are kept in series in a circuit , the same current passes through each of them , but as their resistance are f=different in general , the terminal potential differences are also unequal . On the other hand , each conductor has the same terminal potential difference in a parallel combination , however , the curents through them are different . The terminal potential difference and the currents through two conducting wires are both in the ratio 2 : 1 The ratio of the rates of heat evolved in them is
A
`1:1`
B
`2:1`
C
`4:1`
D
`8:1`
Similar Questions
Explore conceptually related problems
A uniform magnetic field of 100 G (IG=10^(-4)T) exists in a region of length about 10 cm and area of cross- section about 10^(-3)m^(2) . The maximum current carrying capacity of a given coil of wire is 15A and the number of turns per unit length that can be wound round a core is at most 1000 turns m^(-1) . How would you utils the coil to design a solenoid for the required purpose ? Assume the core is not ferromagnetic.
Two metallic conductors A and B of same lengths have resistivities of 1.6xx10^(-8) Omegam and 3.2xx10^(-8) Omega m respectively. These two conductors are separately connected to the same potential difference. What should be the ratio of their cross sections in order to have the same current flowing through each of them?
The cross-sections of the two sides of a U-tube are 1cm^(2)and0.1cm^(2) respectively. Some water is poured inside the tube when it rise to the same height in both the limbs. What volume of a liquid of density 0.85g*cm^(-3) should be poured into the wider limb so that the water level rises by 15 cm in the narrow limb?
Two syringes of different cross sections filled with water are connected with a tightly fitted rubber tube filled with water . Diameters of the smaller piston and larger piston are 1,0 cm and 3.0 cm respectively. (a) Find the force exerted on the larger piston when a force of 10N is applied to the smaller piston. (b) If the smaller piston is pushed in through 6.0 cm, how much does the larger piston move out?
Let us take an electrical conductor in which the electrical energy supplied is entirely converted into heat . If , for the conductor , the terminal potential difference = V , the curent through it = I and its resistance = R , then the electrical energy cnsumed in its t is , W=I^(2)t (from Ohm'slaw R=(V)/(I) ) . So , if thr electrical and the heat energies both are expressed in joule , the heat developed in tiem t is H=I^(2)Rt . However , If H is expressed in the conventional unit calorie , then from the law , W = JH , we may write H=(I^(2)Rt)/(J) , where , J = mechanical equivalent of heat =4.2J."cal"^(-1) . The resistance R of a conducting wire depends on its material , its length l and its area of cross section a .The resistivity of the meterial of the conductor is , rho=(RA)/(l) . When more than one heat -producing conductors are kept in series in a circuit , the same current passes through each of them , but as their resistance are f=different in general , the terminal potential differences are also unequal . On the other hand , each conductor has the same terminal potential difference in a parallel combination , however , the curents through them are different . The first one of two wires ,m of the same meterial and of equal cross section , is longer than the second . A current through their series combination produces heat in them at the rates h_(1)andh_(2) ,respectively .