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NCERT BANGLISH-DIFFERENTIAL EQUATIONS-EXERCISE - 9.2
- In each of the Exercises 1 to 10 vrify that the given functions(expli...
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- y = x^(2) + 2x + C : y' - 2x - 2 = 0
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- y = cos x + C : y' + sin x = 0
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- y = sqrt(1 + x^(2)) : y' = (xy)/(1 + x^(2))
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- y = Ax : xy' = y (x ne 0)
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- y = x sin x : xy' = y + x sqrt(x^(2) - y^(2))(x ne 0 and x gt y or x ...
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- xy = log y + C : y' = (y^(2))/(1 - xy)(xy ne 1)
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- y - cos y = x : (y sin y + cos y + x)y' = y
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- x + y = tan^(-1)y : y^(2)y' + y^(2) + 1 = 0
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- y = sqrt(a^(2) - x^(2)) x ne (-a, a) : x + y (dy)/(dx) = 0(y ne 0)
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- The number of arbitary constants in the general solution of a differe...
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- The number of arbitary constants in the particular solution of a diff...
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