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A pebble of mass 0.05 kg is thrown vert...

A pebble of mass 0.05 kg is thrown vertically upwards. Give the direction and magnitude of the net force on the pebble, (a) during its upward motion, (b) during its downward motion, (c) at the highest point where it is momentarily at rest. Do your answers change if the pebble was thrown at an angle of `45^@` with the horizontal direction? Ignore air resistance.

Text Solution

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The only force in each case is the force of gravity, (neglecting effects of air) equal to 0.5 N vertically downward. The answers do not change, even if the motion of the pebble is not along the vertical. The pebble is not at rest at the highest point. It has a constant horizontal component of velocity throughout its motion.
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Knowledge Check

  • A stone of mass 0.05 kg is thrown in vertical by upward direction (take g = 10 m cdot s^(-2) ). Neglect air friction. The net force acting on the stone during its downwards motion is

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    0.5 N, upward
    B
    0.5 N, downward
    C
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    D
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    0.5 N, upward
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