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Show that 3^(n) xx 4^(m) cannot end wit...

Show that `3^(n) xx 4^(m)` cannot end with the digit 0 or 5 for any natural numbers ‘n’and 'm'

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Knowledge Check

  • For any 'n', 6^(n) - 5^(n) ends with

    A
    1
    B
    6
    C
    5
    D
    4

  • If f : N xx N rarr N is such that f (m,n) = m+n , for all n in N , where N is the set of all natural numbers, then which of the following is true?

    A
    f is one-one but not onto
    B
    f is neither one-one nor onto
    C
    f is one-one and onto
    D
    f is onto but not one-one

  • For any integer n, 6^(n) always ends with

    A
    2
    B
    1
    C
    4
    D
    6

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    Statement-1 : The variance of first n even natural numbers is (n^(2)-1)/(4) Statement-2 : The sum of first n natural number is (n(n+1))/(2) and the sum of the squares of first n natural number is (n(n+1)(2n+1))/(6) .

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