Can the number 6^n, n being a natural nu...

Can the number `6^n`, n being a natural number, end with the digit 5? Give reason.

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For a natural number n which one is the correct statement?

a. `1^(3)+2^(3)+3^(3)+.. . .+n^(3) =(1+2+3+.. .+n)^(2)`

b.`1^(3)+2^(3)+3^(3)+.. . .+n^(3)gt(1+2+3+.. .+n)^(2)`

c.`1^(3)+2^(3)+3^(3)+.. . .+n^(3) lt(1+2+3+.. .+n)^(2)`

d.`1^(3)+2^(3)+3^(3)+.. . .+n^(3) ne(1+2+3+.. .+n)^(2)`

The variance of the first n natural numbers is :

`(n^(2) + 1)/(12)`

`(n^(2) - 1)/(12)`

`(n^(2) - 1)/(6)`

None of these

Total number of 6-digit numbers in which all the odd digit appear is

`(5)/(2) xx 6 !`

`6 !`

`(1)/(2) xx 6 ! `

`(3)/(2) 6 !`