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The base of an equilateral triangle with...

The base of an equilateral triangle with side 2a lies along the y-axis such that the mid-point of the base is at the origin. Find vertices of the triangle.

Text Solution

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The correct Answer is:
`(0, a), (0, -a) " and " (- sqrt3 a, 0) " or " (0, a) , (0, -a) , " and " (sqrt 3a , 0)`
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Knowledge Check

  • The altitude of an equilateral triangle having the length of its side 12 cm is

    A
    12 cm
    B
    `6sqrt2` cm
    C
    6 cm
    D
    `6sqrt3`cm

  • The area of the triangle whose sides are along x=0, y=0 and 4 x+5 y=20 is

    A
    20
    B
    10
    C
    `(1)/(10)`
    D
    `(1)/(20)`

  • Three point-mases m_(1),m_(2)andm_(3) are located at the vertices of an equilateral triangle of side a. What is the moment of inertia of the system about an axis along the altitude of the triangle passing through m_(1) ?

    A
    `(m_(1)+m_(2))(a^(2))/(4)`
    B
    `(m_(1)+m_(2)+m_(3))(a^(2))/(4)`
    C
    `(m_(2)+m_(3))(a^(2))/(4)`
    D
    `(m_(1)+m_(3))(a^(2))/(4)`

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    ABC is an equilateral triangle of side 2a. Find each of its altitudes.

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    The equation of base of an equilateral triangle is x+y=2 and vertex is (2, -1). Then the length of the side of the triangle equals:

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