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Find the centre of mass of a uniform L-s...

Find the centre of mass of a uniform L-shaped lamina (a thin flat plate) with dimensions as shown. The mass of the lamina is 3 kg.

Text Solution

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Choosing the X and Y axes as shown in Fig. 7.11 we have the coordinates of the vertices of the L-shaped lamina as given in the figure. We can think of the L-shape to consist of 3 squares each of length 1m. The mass of each square is 1kg, since the lamina is uniform. The centres of mass `C_(1), C_(2) and C_(3)` of the squares are, by symmetry, their geometric centres and have coordinates (1/2,1/2), (3/2,1/2), (1/2,3/2) respectively. We take the masses of the squares to be concentrated at these points. The centre of mass of the whole L shape (X, Y) is the centre of mass of these mass points.

Hence
`X=([1(1//2)+1(3//2)+1(1//2)]kgm)/((1+1+1)kg)=(5)/(6)m`
`Y=([1(1//2)+1(1//2)+1(3//2)]kgm)/((1+1+1)kg)=(5)/(6)m`
The centre of mass of the L-shape lies on the line OD. We could have guessed this without calculations. Can you tell why? Suppose, the three squares that make up the L shaped lamina of Fig. 7.11 had different masses. How will you then determine the centre of mass of the lamina?
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Knowledge Check

  • Distance of the centre of mass of a solid uniform cone from its vertex is z_(0) . If the radius of its base is Rand its height is h, the z_(0) is equal to :

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  • A particle of mass m and charge q moving with velocity V enters region II normal to the boundary as shown in the figure. Region II has a uniform magnetic field B perpendicular to the plane of the paper .The length of the Region II is l . Choose the correct choice (s).

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    The particle enters region III only if its velocity `V gt (q,B)/(m)`
    B
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    D
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  • 1.3 L of a gas at NTP weighs 3.01 grams. The molecular mass of the gas is

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