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is found experimentally that 13.6 eV ene...

is found experimentally that 13.6 eV energy is required to separate a hydrogen atom into a proton and an electron. Compute the orbital radius and the velocity of the electron in a hydrogen atom.

Text Solution

Verified by Experts

Total energy of the electron in hydrogen atom is `–13.6 eV = –13.6 xx 1.6 × 10^(-19) J = –2.2 xx 10^(–18) J`. Thus from Eq., we have
`E = - (e^2)/(8 pi epsilon_0 r) = -2.2 xx 10^(-18) J`
This gives the orbital radius
`r = (e^2)/(8 pi epsilon_0 E) = ((9 xx 10^(9) N m^2//C^2)(1.6 xx 10^(-19) C)^(2))/((2)(-2.2 xx 10^(-18)J))`
`= 5.3 xx 10^(-11) m`.
The velocity of the revolving electron can be computed from Eq.with `m = 9.1 xx 10^(-31) kg,`
`upsilon = - (e)/(sqrt(4 pi epsilon_0 mr)) = 2.2 xx 10^(6) m//s`.
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Knowledge Check

  • A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

    A
    `3.16 xx 10^(-34)` J s
    B
    `1.05 xx 10^(-34)` J s
    C
    `4.22 xx 10^(-34)` J s
    D
    `2.11 xx 10^(-34)` J s
  • The radius of the first orbit of electron in hydrogen atom (e=1.6xx10^(-19)" coulomb,

    A
    `53Å`
    B
    `0.53Å`
    C
    `5.3Å`
    D
    `53xx10^(2)Å`
  • The energy (in W) required to excite an electron from n = 2 to n = 4 state in hydrogen atom

    A
    `+2.55`
    B
    -3.4
    C
    `+4.25`
    D
    `-0.85`
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