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AD is an altitude of an isosceles triang...

AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that, (i) AD bisects BC (ii) AD bisects `/_ A.`

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Knowledge Check

  • If Delta ABC is an isosceles triangle with hat(C ) = 90^(@) and AC = sqrt(8) cm then AB is :

    A
    4 cm
    B
    4.5 cm
    C
    `sqrt(8)` cm
    D
    16 cm

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