Home
Class 10
MATHS
Diagonals AC and BD of a trapezium ABCD ...

Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point ‘O’. Using the criterion of similarity for two triangles, show that ` (OA)/(OC) = (OB)/(OD)` .

Answer

Step by step text solution for Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point ‘O’. Using the criterion of similarity for two triangles, show that (OA)/(OC) = (OB)/(OD) . by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SIMILAR TRIANGLES

    NCERT TAMIL|Exercise EXERCISE - 8.3|6 Videos

  • SIMILAR TRIANGLES

    NCERT TAMIL|Exercise EXERCISE - 8.4|14 Videos

  • SIMILAR TRIANGLES

    NCERT TAMIL|Exercise EXERCISE - 8.1|9 Videos

  • SETS

    NCERT TAMIL|Exercise Try This|9 Videos

  • STATISTICS

    NCERT TAMIL|Exercise THINK AND DISCUSS|8 Videos

Similar Questions

Explore conceptually related problems

Diagonals of a trapezium ABCD with AB || DC, intersect each other at the point ‘O’. If AB = 2CD, find the ratio of areas of triangles AOB and COD.

squareABCD is a trapezium in which AB|| DC and its diagonals intersect each other at points O . Show that AO : BO = CO : DO.

If 'O' is any point in the interior of rectangle ABCD, then prove that : OB^(2) + OD^(2) = OA^(2) + OC^(2)

The diagonals of a quadrilateral ABCD intersect each other at point ‘O’ such that (AO)/(BO) = (CO)/(DO) . Prove that ABCD is a trapezium

The diagonal AC of a parallelogram ABCD intersects DP at the point Q, where ‘P’ is any point on side AB. Prove that CQ xx PQ = QA xx QD .

ABCD is a quadrilateral and E is the point of intersection of the lines joining the middle points of opposite side. Show that the resultant of vec (OA) , vec(OB) , vec(OC) and vec(OD) = 4 vec(OE) , where O is any point.

In trapezium ABCD, AB || DC. E and F are points on non-parallel sides AD and BC respectively such that EF || AB. Show that (AE)/(ED) = (BF)/(FC)

In trapezium ABCD , side AB||DC Diagonals AC and BD intersect in O . If AB=20,DC=6, OB=15 . Find OD.

ABCD is trapezium with AB || DC. The diagonal AC and BD intersect at E . If Delta AED ~ Delta BEC . Prove that AD = BC .

In squareABCD, "seg " AD||"seg " BC. Diagonal AC and diagonal BC intersect each other in point P. Then show that (AP)/(PD)=(PC)/(BP)

Home
Profile