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The enthalpy change (Delta H) for the re...

The enthalpy change `(Delta H)` for the reaction
`N_(2) (g) + 3 H_(2) (g) rarr 2 NH_(3) (g)`
is `- 92.38 kJ` at `298 K`. The internal energy change `Delta U` at `298 K` is

A

`-92.38 kJ`

B

`-87.42 kJ`

C

`-97.34 kJ`

D

`-89.9 kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH=DeltaU+Deltan_(g)RT`
`Deltan_(g)=-2`.
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The enthalpy change (Delta H) for the reaction N_(2) (g)+3H_(2)(g) rarr 2NH_(3)(g) is -92.38 kJ at 298 K . What is Delta U at 298 K ?

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