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Energy required to dissociate 4g of gase...

Energy required to dissociate `4g` of gaseous hydrogen into free gaseous atoms is `208Kcal` at `25^(@)C`
The bond energy of `H-H` bond will be

A

104 kcal

B

10.4 kcal

C

1040 kcal

D

104 cal

Text Solution

Verified by Experts

The correct Answer is:
A
4g `H_(2)=2` moles. Bond energy for 1 mole of `H_(2)=208//2=104` kcal.
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Knowledge Check

  • Energy required to dissociate 4 g of gaseous hydrogen into free gaseous atom is 208 Kcal at 25^(@)C . The bond energy of H-H bond will be

    A
    1.04 Kcal
    B
    10.4 Kcal
    C
    104 Kcal
    D
    1040 Kcal

  • Energy required to dissociate 4 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25^(@)C . The bond energy of H-H will be

    A
    104 kcal
    B
    52kcal
    C
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    D
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  • Energy requried to dissociate 4 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25^(@)C . The bond energy of H-H will be

    A
    104 kcal `mol^(-1)`
    B
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    C
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    D
    1040 kcal `mol^(-1)`

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