Which of the following will not produce a precipitate with `AgNO_(3)` solution

Options

A. `F^(-)`
B. `Br^(-)`
C. `CO_(3)^(2-)`
D. `PO_(4)^(3-)`

Explanation

To determine which of the given ions will not produce a precipitate with AgNO₃ (silver nitrate) solution, we need to analyze the common ions that typically react with AgNO₃ to form precipitates.

### Step-by-Step Solution:

1. **Understanding Precipitation Reactions**:
- Silver nitrate (AgNO₃) is a soluble salt that dissociates in water to form Ag⁺ and NO₃⁻ ions.
- When Ag⁺ ions encounter certain anions (like Cl⁻, Br⁻, I⁻), they can form insoluble silver salts (precipitates).

2. **Common Anions that Form Precipitates**:
- **Chloride (Cl⁻)**: Forms AgCl, which is a white precipitate.
- **Bromide (Br⁻)**: Forms AgBr, which is a pale yellow precipitate.
- **Iodide (I⁻)**: Forms AgI, which is a yellow precipitate.

3. **Anions that Do Not Form Precipitates**:
- **Fluoride (F⁻)**: Silver fluoride (AgF) is soluble in water, meaning it will not form a precipitate.
- **Nitrate (NO₃⁻)**: Silver nitrate itself is soluble and does not form a precipitate.

4. **Conclusion**:
- Among the common anions, fluoride (F⁻) will not produce a precipitate with AgNO₃ solution.

### Final Answer:
The ion that will not produce a precipitate with AgNO₃ solution is **Fluoride (F⁻)**.