A white crystalline substance dissolves in water.On passing `H_(2)S` in this solution, a black precipitate is obtained.The black precipitate dissolves completely in hot `HNO_(3)`.On adding a few drops of concentrated `H_(2)SO_(4)`, a white precipitate is obtained.This precipitate is that of

Options

A. `BaSO_(4)`
B. `SrSO_(4)`
C. `PbSO_(4)`
D. `CdSO_(4)`

Answer

C

Explanation

`Pb^(+2)+H_(2)S underset(acidic)tounderset(("black ppt."))(PbS)darr+H_(2)uarr`
`3PbS+8HNO_(3)to3Pb(NO_(3))_(2)+2NO+3S+4H_(2)O`
`Pb(NO_(3))_(2)+H_(2)SO_(4)to underset(("white ppt."))(PbSO_(4))darr+2HNO_(3)uarr`