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An object is moving with uniform acceler...

An object is moving with uniform acceleration a. Its initial velocity is u and after time t its velocity is v. The equation of its motion is v = u + at. The velocity (along y-axis) time (along x-axis) graph shall be a straight line

A

passing through origin

B

with x-intercept u

C

with y-intercept u

D

with slope u

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To solve the problem step by step, we will analyze the motion of an object with uniform acceleration and derive the corresponding velocity-time graph. ### Step 1: Understand the given equation The equation of motion for an object moving with uniform acceleration is given by: \[ v = u + at \] where: - \( v \) = final velocity - \( u \) = initial velocity - \( a \) = acceleration - \( t \) = time ### Step 2: Identify the variables for the graph In this scenario, we will plot: - The y-axis will represent the velocity \( v \). - The x-axis will represent the time \( t \). ### Step 3: Rearrange the equation We can rearrange the equation \( v = u + at \) to fit the form of a straight line equation \( y = mx + c \): - Here, \( v \) (velocity) is the dependent variable (y-axis). - \( t \) (time) is the independent variable (x-axis). - The equation can be rewritten as: \[ v = at + u \] This shows that: - The slope \( m \) of the line is equal to the acceleration \( a \). - The y-intercept \( c \) is equal to the initial velocity \( u \). ### Step 4: Graph the equation Now, we can sketch the graph: - Start by plotting the y-intercept \( u \) on the y-axis. - Since the slope is \( a \), for every unit increase in \( t \), \( v \) increases by \( a \). - Draw a straight line starting from the point \( (0, u) \) and extending upwards with a slope of \( a \). ### Step 5: Analyze the graph The graph will be a straight line: - The slope of the line represents the acceleration \( a \). - The point where the line intersects the y-axis represents the initial velocity \( u \). ### Conclusion Thus, the velocity-time graph for an object moving with uniform acceleration is a straight line with: - Slope = \( a \) (acceleration) - Y-intercept = \( u \) (initial velocity)

To solve the problem step by step, we will analyze the motion of an object with uniform acceleration and derive the corresponding velocity-time graph. ### Step 1: Understand the given equation The equation of motion for an object moving with uniform acceleration is given by: \[ v = u + at \] where: - \( v \) = final velocity - \( u \) = initial velocity ...
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Knowledge Check

  • For body moving with uniform acceleration a , initial and final velocities in a time interval t are u and v respectively. Then its average velocity in the time interval t is

    A
    `(v+at)`
    B
    `(v-(at)/(2))`
    C
    `(v-at)`
    D
    `(u-(at)/(2))`
  • For a body moving with uniform acceleration along straight line, the variation of its velocity (v) with position (x) is best represented by

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    B
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  • At the start of a motion along a line the initial velocity is u and acceleration is at. The final velocity v after time t, is

    A
    `v=u+at`
    B
    `v=u+at^(2)`
    C
    `v=u+(1)/(2)at^(2)`
    D
    `v=at^(2)`
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