How many gram atoms of hydrogen are present in 0.04 mole of `CuSO_(4), 5H_(2)O` ?

Options

A. 0.04
B. 0.2
C. 0.4
D. 4

Explanation

To determine how many gram atoms of hydrogen are present in 0.04 moles of `CuSO4·5H2O`, we can follow these steps:

### Step 1: Identify the number of hydrogen atoms in one formula unit of `CuSO4·5H2O`.
`CuSO4·5H2O` contains 5 water molecules (H2O). Each water molecule has 2 hydrogen atoms. Therefore, in 5 water molecules, the total number of hydrogen atoms is:
\[ 5 \text{ H}_2\text{O} \times 2 \text{ H} = 10 \text{ H atoms} \]

### Step 2: Determine the number of hydrogen atoms in 1 mole of `CuSO4·5H2O`.
Since 1 mole of `CuSO4·5H2O` contains 10 hydrogen atoms, we can say that 1 mole of `CuSO4·5H2O` contains 10 gram atoms of hydrogen.

### Step 3: Calculate the number of hydrogen atoms in 0.04 moles of `CuSO4·5H2O`.
To find the number of hydrogen atoms in 0.04 moles, we can use a unitary method. We know that:
- 1 mole of `CuSO4·5H2O` has 10 gram atoms of hydrogen.
- Therefore, in 0.04 moles, the number of gram atoms of hydrogen can be calculated as:
\[ \text{Number of gram atoms of H} = 10 \text{ (gram atoms in 1 mole)} \times 0.04 \text{ (moles)} \]
\[ = 0.4 \text{ gram atoms of H} \]

### Final Answer:
Thus, the number of gram atoms of hydrogen present in 0.04 moles of `CuSO4·5H2O` is **0.4 gram atoms**.

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