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The number of arrangements that can be m...

The number of arrangements that can be made with the letters of the word 'MATHEMATICS' in which all vowels comes together, is

A

`(8!xx4!)/(2!2!)`

B

`(8!xx4!)/(2!2!2!)`

C

`(8!)/(2!2!2!)`

D

`(8!)/(4!2!2!)`

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The correct Answer is:
To find the number of arrangements of the letters in the word "MATHEMATICS" where all vowels come together, we can follow these steps: ### Step 1: Identify the vowels and consonants The word "MATHEMATICS" consists of the following letters: - Vowels: A, A, E, I (4 vowels) - Consonants: M, T, H, M, T, C, S (7 consonants) ### Step 2: Treat all vowels as a single unit Since we want all vowels to come together, we can treat the group of vowels (A, A, E, I) as a single unit or letter. Therefore, we will have: - Vowel group: (AAEI) - Consonants: M, T, H, M, T, C, S This gives us a total of 8 "letters" to arrange: - 1 vowel group + 7 consonants = 8 units ### Step 3: Calculate the arrangements of the 8 units The total arrangements of these 8 units (considering that M and T are repeated) can be calculated using the formula for permutations of multiset: \[ \text{Arrangements} = \frac{8!}{2! \times 2!} \] Where: - \(8!\) is the factorial of the total units (8) - \(2!\) accounts for the two M's - \(2!\) accounts for the two T's ### Step 4: Calculate the arrangements of the vowels Next, we need to arrange the vowels within their group (AAEI). The arrangement of these vowels can be calculated as: \[ \text{Vowel arrangements} = \frac{4!}{2!} \] Where: - \(4!\) is the factorial of the total vowels (4) - \(2!\) accounts for the two A's ### Step 5: Calculate the total arrangements Now, we multiply the arrangements of the 8 units by the arrangements of the vowels: \[ \text{Total arrangements} = \left(\frac{8!}{2! \times 2!}\right) \times \left(\frac{4!}{2!}\right) \] ### Step 6: Substitute the factorial values and calculate Calculating the factorials: - \(8! = 40320\) - \(4! = 24\) - \(2! = 2\) Now, substituting these values: \[ \text{Total arrangements} = \left(\frac{40320}{2 \times 2}\right) \times \left(\frac{24}{2}\right) \] \[ = \left(\frac{40320}{4}\right) \times 12 \] \[ = 10080 \times 12 = 120960 \] ### Final Answer The total number of arrangements of the letters in "MATHEMATICS" where all vowels come together is **120960**. ---

To find the number of arrangements of the letters in the word "MATHEMATICS" where all vowels come together, we can follow these steps: ### Step 1: Identify the vowels and consonants The word "MATHEMATICS" consists of the following letters: - Vowels: A, A, E, I (4 vowels) - Consonants: M, T, H, M, T, C, S (7 consonants) ### Step 2: Treat all vowels as a single unit ...
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