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A 3.0 cm object is placed 8.0 cm in fron...

A 3.0 cm object is placed 8.0 cm in front of a mirror.The virtual image is 4.0 cm further from the mirror when the mirror is concave than when it is planar.
Determine the focal length of the concave mirror.

A

6.0 cm

B

24 cm

C

12 cm

D

48 cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the information provided in the question and apply the mirror formula. ### Step 1: Identify the Object Distance We are given that the object distance (u) is 8.0 cm in front of the mirror. According to the sign convention for mirrors, distances measured in the direction of the incident light (towards the mirror) are negative. Therefore: \[ u = -8.0 \, \text{cm} \] ### Step 2: Determine the Image Distance for the Plane Mirror For a plane mirror, the image distance (v) is equal to the object distance but on the opposite side of the mirror. Thus: \[ v_{\text{plane}} = +8.0 \, \text{cm} \] ### Step 3: Determine the Image Distance for the Concave Mirror According to the problem, the virtual image formed by the concave mirror is 4.0 cm further from the mirror than the image formed by the plane mirror. Therefore, the image distance for the concave mirror is: \[ v_{\text{concave}} = v_{\text{plane}} + 4.0 \, \text{cm} = 8.0 \, \text{cm} + 4.0 \, \text{cm} = 12.0 \, \text{cm} \] Since this image is virtual and behind the mirror, we take it as positive: \[ v = +12.0 \, \text{cm} \] ### Step 4: Apply the Mirror Formula The mirror formula is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] Substituting the values we have: \[ \frac{1}{f} = \frac{1}{12.0} + \frac{1}{-8.0} \] ### Step 5: Calculate the Right Side of the Equation Calculating the right side: \[ \frac{1}{f} = \frac{1}{12} - \frac{1}{8} \] To combine these fractions, we need a common denominator, which is 24: \[ \frac{1}{f} = \frac{2}{24} - \frac{3}{24} = \frac{-1}{24} \] ### Step 6: Solve for the Focal Length Taking the reciprocal gives us the focal length: \[ f = -24.0 \, \text{cm} \] ### Conclusion The focal length of the concave mirror is: \[ \boxed{-24.0 \, \text{cm}} \] ---
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Knowledge Check

  • A 3.0 cm object is placed 8.0 cm in front of a mirror.The virtual image is 4.0 cm further from the mirror when the mirror is concave than when it is planar. Determine the image height in the concave mirror.

    A
    `0.5`
    B
    `4.5`
    C
    `1.5`
    D
    `3.0`
  • An object is placed 10 cm in front of a convex mirror of focal length 20 cm . The distance of the image from the mirror is

    A
    10/3 cm
    B
    20/3 cm
    C
    10 cm
    D
    40/3 cm
  • If an object is placed 10 cm infront of a concave mirror of focal length 20cm, the image will be

    A
    Diminished, upright, virtual
    B
    Enlarged, upright, virtual
    C
    Diminished, inverted, real
    D
    Enlarged, upright, real
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