(i) Prove that depression in freezing point is a colligative property.
(ii) 45 g of ethylene glycol `(C_(2)H_(6)O_(2))` is mixed with 600g of water . Calculate the freezing point depression. (`K_(f)` for water = 1.86 k kg `mol^(-1)`)

Explanation

### Step-by-Step Solution

#### Part (i): Proving that Depression in Freezing Point is a Colligative Property

1. **Definition of Colligative Properties**:
- Colligative properties are properties that depend on the number of solute particles in a solution and not on the nature or identity of the solute.

2. **Understanding Freezing Point Depression**:
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