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The standard Gibbs free energy change (D...

The standard Gibbs free energy change `(DeltaG^(@))` at `25^(@)C` for the dissociation of `N_(2)O_(4(g))` to `NO_(2(g))` is
(given, equilibrium cont. `=0.15,R=8.314JK^(-1)mol^(-1)`)

A

1.1 kJ

B

4.7 kJ

C

8.1 kJ

D

38.2 kJ

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG^(@)=-RTlnK`
`=-2.303xx8.314xxlog0.15=4.7kJ`
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Knowledge Check

  • The standard Gibbs free energy change (DeltaG^(@)) at 25^(@)C for the dissociation of N_(2)O_(4)(g) to NO_(2)(g) is (given, equilibrium constant = 0.15, R=8.314 JK^(-) mol^(-1) )

    A
    1.1 KJ
    B
    4.7 KJ
    C
    8.1 KJ
    D
    38.2 KJ

  • The standard Gibbs free energy change (DeltaG^0 ) 25°C for the dissocitation of N_(2)O_(4(g)) "to"NO_(2(g) (given equilibrium constant = 0.15, R = 8.314 JK^(-1)mol^(-1)

    A
    1.1 kJ
    B
    4.7 kJ
    C
    8.1 kJ
    D
    38.2 kJ

  • find out the standard free energy change at 60^(@)C and at 1 atn if the N_(2)O_(4) is 50 % dissociated

    A
    `-800 .0 kJ mol^(-1)`
    B
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    C
    `789.89 JK^(-1) mol^(-1)`
    D
    `+ 789.98 JK^(-1)mol ^(-1)`

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