Home
Class 10
MATHS
Show that any number of the form 4^(n),...

Show that any number of the form ` 4^(n), n = N` can never end with the digit `0`.

Answer

Step by step text solution for Show that any number of the form 4^(n), n = N can never end with the digit 0. by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REAL NUMBERS

    VK GLOBAL PUBLICATION|Exercise Short Answer Questions -II|11 Videos

  • REAL NUMBERS

    VK GLOBAL PUBLICATION|Exercise Long Answer Questions|8 Videos

  • REAL NUMBERS

    VK GLOBAL PUBLICATION|Exercise Self -Assessment Test|11 Videos

  • QUADRATIC EQUATIONS

    VK GLOBAL PUBLICATION|Exercise SELF-ASSESSMENT TEST|11 Videos

  • TRIANGLES

    VK GLOBAL PUBLICATION|Exercise SELF ASSESSMENT TEST|10 Videos

Similar Questions

Explore conceptually related problems

Show that any number of the form 4^(n),n ne N can never end with the digit 0.

Show that any number of the form 6^(n) , where n ne N can never and with the digit 0.

Knowledge Check

  • Number of divisors of the form 4n + 2, n ge 0 which can divide 240 is :

    A
    4
    B
    8
    C
    10
    D
    3

    • Similar Questions

    Explore conceptually related problems

    Consider the numbers 4^(n) , where n is a natural number. Check whether there is any value of n for which 4^(n) ends with the digit zero.

    Can the number 6^(n),n being a natural number, end with the digit 5? Give reason.

    Prove that there is no natural number for which 4^(n) ends with the digit zero.

    The number of all 4-digit number of the form 5n+2 (n in n) having exactly one digit 7

    Can the number 9^(n) , n being a natural number, end with the digit 5 ? Give reasons

    n-digit number

    Show that 9^n cannot end with the digit 2 for any n in N .

    Home
    Profile