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AB is a diameter of a circle and AC is i...

AB is a diameter of a circle and AC is its chord such that `angleBAC=30^(@)`. If the tengent at C intersects AB extended at D, then BC=BD.

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Knowledge Check

  • AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Find the angle AEB .

    A
    `30^(@)`
    B
    `60^(@)`
    C
    `90^(@)`
    D
    `45^(@)`
  • AD is a diameter of a circle and AB is a chord. If AD = 34cm, AB = 30cm, the distance of AB form the centre of the circle is

    A
    `17` cm
    B
    `15` cm
    C
    `4` cm
    D
    `8` cm
  • In a circle of radius 5 cm, AB and AC are the two chords such that AB=AC=6cm. Find the length of the chord BC

    A
    4.8 cm
    B
    10.8cm
    C
    9.6 cm
    D
    none of these
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