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What is the area of a square inscribed i...

What is the area of a square inscribed in a circle of diameter x cm?

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To find the area of a square inscribed in a circle with a diameter of \( x \) cm, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the relationship between the square and the circle**: - The square is inscribed in the circle, meaning all four corners of the square touch the circumference of the circle. 2. **Identify the diameter of the circle**: - Given that the diameter of the circle is \( x \) cm. 3. **Determine the radius of the circle**: - The radius \( r \) of the circle is half of the diameter. \[ r = \frac{x}{2} \text{ cm} \] 4. **Relate the side of the square to the radius of the circle**: - Let the side length of the square be \( a \) cm. The diagonal of the square is equal to the diameter of the circle. - By the properties of a square, the diagonal \( d \) can be expressed in terms of the side length \( a \) using the Pythagorean theorem: \[ d = a\sqrt{2} \] - Since the diagonal of the square is also equal to the diameter of the circle, we have: \[ a\sqrt{2} = x \] 5. **Solve for the side length \( a \)**: - Rearranging the equation gives: \[ a = \frac{x}{\sqrt{2}} \] 6. **Calculate the area of the square**: - The area \( A \) of the square is given by: \[ A = a^2 \] - Substituting the expression for \( a \): \[ A = \left(\frac{x}{\sqrt{2}}\right)^2 = \frac{x^2}{2} \text{ cm}^2 \] ### Final Answer: The area of the square inscribed in a circle of diameter \( x \) cm is: \[ \frac{x^2}{2} \text{ cm}^2 \]
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Knowledge Check

  • Find the area of a square inscribed in a circle of radius 4 cm.

    A
    32 sq cm
    B
    18 sq cm
    C
    64 sq cm
    D
    25 sq cm
  • The area of the square inscribed in a circle of radius 8 cm is

    A
    256 sq. cm
    B
    250 sq. cm
    C
    128sq. Cm
    D
    125 sq. cm
  • A circle is inscribed in an equilateral triangle of side a. What is the area of any square inscribed in the circle ?

    A
    `(a^(2))/(3)`
    B
    `(a^(2))/(4)`
    C
    `(a^(2))/(6)`
    D
    `(a^(2))/(8)`
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