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Give A^(@)(1/3 Al^(3+))=63 Omega^(-1) cm...

Give `A^(@)(1/3 Al^(3+))=63 Omega^(-1) cm^(2) mol^(-1)` and `Lambda^(@)(1/2 SO_(4)^(2)) = 80 Omega^(-1)`. The value of `Lambda^(oo)Al_(2)(SO_4)_3` would be

A

`143 Omega^(-1) cm^(2) mol^(-1)`

B

`206 Omega^(-1) cm^(2) mol^(-1)`

C

`286 Omega^(-1) cm^(2) mol^(-1)`

D

`858 Omega^(-1) cm^(2) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`Lambda^(@)""_((Al^3+)=Lambda^(@)""_((1/3Al^(3+)))`
`=3 xx 63 =189 Omega^(-1) cm^(2) mol^(-1)Lambda^(@)""_((SO_4^(2-)))=2Lambda^(@)""_((1/2SO_(4)^(2-)))`
`=2 xx 80 =160 Omega^(-1) cm^(2) mol^(-1) =858 Omega^(-1) cm^2 mol^(-1)`
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