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A capacitor of capacitance C(0) is charg...

A capacitor of capacitance `C_(0)` is charged to a potential `V_(0)` and is connected with another capacitor of capacitance C as Shown . After closing the switch S, the common potential across the two capacitors becomes V . The capacitance C is given by

A

`(C_(0)(V_(0)-V))/(V_(0))`

B

`(C_(0)(V-V_(0)))/(V_(0))`

C

`(C_(0)(V+V_(0)))/(V)`

D

`(C_(0)(V_(0)-V))/(V)`

Text Solution

Verified by Experts

The correct Answer is:
d
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Knowledge Check

  • A capacitor of capacitance C_0 is charged to potential V_0 . Now it is connected to another uncharged capacitor of capacitance C_0/2 . Calculate the heat loss in this process.

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