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The equilibrium constant Kc for A((g))hA...

The equilibrium constant Kc for `A_((g))hArrB_((g))` is `2.5xx10^(-2)`. The rate constant of the forward reaction is `0.05" sec"^(-1)`. Calculate the rate constant of the reverse reaction.

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The correct Answer is:
`2.0" sec"^(-1)`
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