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The non - stoichiometric iron oxide has ...

The non - stoichiometric iron oxide has a composition `Fe_(0.94) O`. Find the ratio of ferrous and ferric ions present in it.

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Say one hundred ions of each `Fe^(2+) and O^(2-)` present in the stoichiometric `FeO`. Some of `Fe^(2+)` ions (x) are replaced by `Fe^(3+)` ions (y).
In view of the conservation of ions in an ionic crystal,
`x+y=94 " "…(1)`
In view of the conservation of positive charge of cations in a crystal,
`2x+3y = 200" "...(2)`
Solving, for .x. and for .y.,
`y=12 and x=82`
The ration of `Fe^(2+) and Fe^(3+)` ions present in `Fe_(0.94) O =82 : 12`
`= 41:6`
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Knowledge Check

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