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In a triangle ABC , let angleC=(pi)/2. I...

In a triangle ABC , let `angleC=(pi)/2`. If r is the in-radius and R is the circum-radius of the triangle , then 2 (r + R) is equal to

A

b+c

B

c+a

C

a+b

D

a+b+c

Text Solution

Verified by Experts

The correct Answer is:
c
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Knowledge Check

  • In triangle ABC, let angle C = pi//2 . If r is the inradius and R is circumradius of the triangle, then 2(r + R) is equal to

    A
    `a + b`
    B
    `b + c`
    C
    `c + a`
    D
    `a + b + c`

  • In a triangle ABC if r_1=R , then

    A
    `cos A+ cos B = cos C`
    B
    `cos B+ cos C = cos A`
    C
    `cos C+ cos A = cos B`
    D
    `cos A+ cos B + cos C = 1`

  • If R is the circum radius of DeltaABC , then A (DeltaABC) = . . .

    A
    `(abc)/(R)`
    B
    `(abc)/(4R)`
    C
    `(abc)/(3R)`
    D
    `(abc)/(2R)`

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