Home
Class 12
MATHS
A particle is projected vertically upwar...

A particle is projected vertically upward and is at a height h after `t_(1)` seconds and again after `t_(2)` seconds

A

`h="gt"_(1)t_(2)`

B

`h=(1)/(2)"gt"_(1)t_(2)`

C

`h=(2)/(g)t_(1)t_(2)`

D

`h=sqrt("gt"_(1)t_(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    MTG-WBJEE|Exercise WB JEE WORKOUT ( CATEGORY 2 : Single Option Correct Type (2 Marks) )|15 Videos

  • APPLICATION OF DERIVATIVES

    MTG-WBJEE|Exercise WB JEE WORKOUT ( CATEGORY3 : One or More than One Option Correct Type (2 Marks)|15 Videos

  • A.P.,G.P.,H.P.

    MTG-WBJEE|Exercise WB JEE Previous Years Questions ( CATEGORY 2 : Single Option Correct Type (2 Mark ) )|5 Videos

  • APPLICATION OF INTEGRALS

    MTG-WBJEE|Exercise WE JEE PREVIOUS YEARS QUESTIONS (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|3 Videos

Similar Questions

Explore conceptually related problems

A particle is projected vertically upwards and is at a height h after t_(1) seconds and again after t_(1) seconds then h=(1)/(2)"gt"_(1)t_(2) .

A body is projected vertically upwards at time "t=0" and it is seen at a height H at instants t_(1) and t_(2)seconds during its flight.The maximum height attained is (g is acceleration due to gravity

Knowledge Check

  • A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

    A
    `g (t - T)2`
    B
    `H - 1/2g (t - T)^2`
    C
    `g (t - T)2`
    D
    `H - g (t - T)`

  • A stone projected vertically up from the ground reaches a height y in its path at t_(1) seconds and after further t_(2) seconds reaches the ground. The height y is equal to

    A
    `(1)/(2)g(t_(1)+t_(2))`
    B
    `(1)/(2)g(t_(1)+t_(2))^(2)`
    C
    `(1)/(2)g t_(1)t_(2)`
    D
    `g t_(1)t_(2)`

  • A particle is projected vertically upwards and reaches the maximum height H in time T. The height of the partlcle at any time t (lt T) will be

    A
    `g (t-T)^2`
    B
    `H - g (t-T)^2`
    C
    `1/2 g (t-T)^2`
    D
    `H - 1/2 g (T-t)^2`

    • Similar Questions

    Explore conceptually related problems

    A particle is projected vertically upwards and t second after another particle is projected upwards with the same initial velocity. Prove that the particles will meet after a lapse of ((t)/(2)+(u)/(g)) time from the instant of projection of the first particle.

    A particle is projected vertically upwards from O with a velocity and a second particle is projected at the same instant from P (at a height h above O) with velocity v at an angle of projection theta with the horizontal. Find the time when the distance between them is minimum. Take v = 5m//s and h = 20 m

    A particle is projected vertically upwards from a point O on the ground. It takes time t_(1) to reach a point A at a height h above the ground, it continues to move and takes a time t_(2) to reach the ground. Find (a) h, (b) the maximum height reached and (c ) the velocity of the partical at the half of maximum height.

    A particle is projected vertically upwards .Its height H at a time t has the relation h =(60)t-(16)t^(2) . Velocity with which it hits the grounf is

    A ball projected from ground vertically upward is at same height at time t_(1) and t_(2) . The speed of projection of ball is [Neglect the effect of air resistance ]

    Home
    Profile