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pH of a solution is 5.5 at 25^(@)C. Calc...

pH of a solution is 5.5 at `25^(@)C`. Calculate its `[OH^(-)]`

Text Solution

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`pH+pOH=14.0" "thereforepOH=14.0-pH`
`=14.0-5.5=8.50`
`pOH=8.5" "therefore" antilong "[-pOH]`
`therefore[OH^(-)]=" antilog "[-8.5]=3.2xx10^(-9)M`
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