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If z^(1) =2 -I, z(2)=1+i, find |(z(1) + ...

If `z^(1) =2 -I, z_(2)=1+i`, find `|(z_(1) + z_(2) + 1)/(z_(1)-z_(2) + 1)|`

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The correct Answer is:
`sqrt(2)`
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Knowledge Check

  • If |z_(1) | = |z_(2)| = 1 , then |z_(1) + z_(2)| =

    A
    `|(1)/(z_(1)) + (1)/(z_(2))|`
    B
    `| (1)/(z_(1)) - (1)/(z_(2))|`
    C
    `| (1)/(z_(1)) * (1)/(z_(2))|`
    D
    `| (1)/(z_(1)^(2)) + (1)/(z_(2)^(2)))|`

  • If z_(1) = 1 , z_(2) = i and A = Arg (z_(1) z_(2)) B = Arg ((z_(1))/(z_(2))) , C = Arg (z_(1) + z_(2)) , D = Arg (z_(1) - z_(2)) arrange A , B , C , D in ascending order

    A
    A , C ,D , B
    B
    B, D , C , A
    C
    B , C , D , A
    D
    B , A , D , C

    • Similar Questions

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    If z_(1)=-1 and z_(2)=-i , then find Arg (z_(1)z_(2))

    If z_(1)=(2,-1),z_(2)=(6,3) find z_(1)-z_(2)

    If z _(1) =- 1, and z _(2) =- i, then find Arg (z _(1) z _(2))

    If z _(1) =- 1, z _(2) = i, then find Arg ((z _(1))/( z _(2))).

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