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Critical constants are related with van ...

Critical constants are related with van der waals' constant as follows:
`V_( c) = 3b, P_( c) =a/(27b^(2)), T_( c) =(8a)/(27 Rb)`
The pressure required to liquefy a gas at the critical temperature is called :

A

reduced pressure

B

critical pressure

C

vapour pressure

D

atmospheric pressure

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . It was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (Tc). The pressure required to liquefy a gas at this temperature is called the critical pressure (Pc). The volume occupied by one mole of the substance at the critical temperature and pressure is called critical volume. Critical constants are related with van der waals' constant as follows: V_( c) = 3b, P_( c) =a/(27b^(2)), T_( c) =(8a)/(27 Rb) The values of critical volumes of four gases A, B, C and D are 0.025L, 0.312L, 0.245L and 0.432L respectively. The gas with larger molecular diameter will be :

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    At a particular temperature and pressure for a real gas Van der Waal's equation can be written as: (P + a/(V^(2)m)) (V_(m) -b) =RT where Vm is molar volume of gas. This is cubic equation in the variable Vm and therefore for any single value of P & T there should be 3 values of Vm. Which are shown in graph as Q, M and L. As temperature is made to increase at a certain higher temperature the three values of Vm becomes identical. The temperature, pressure & molar volume at point X are called Tc, Pc & Vc for real gas. The compressibility factor in terms of Pc, Vc and T is called Zc. The value of critical compressibility factor Zc is approximately

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