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AT673 K. in the formation of NH(3) From ...

AT673 K. in the formation of `NH_(3)` From `N_(2) and H_(2)` , the partial pressures of `N_(2) , H_(2) and and NH_(3)` at equilibrium are 0.5 , 1 and `9 xx 10^(-3) ` atm respectively. `(N_(2) + 3H_(2) hArr + Q)`
Calculate `K_(c)` for the reaction.

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Knowledge Check

  • AT673 K. in the formation of NH_(3) From N_(2) and H_(2) , the partial pressures of N_(2) , H_(2) and and NH_(3) at equilibrium are 0.5 , 1 and 9 xx 10^(-3) atm respectively. (N_(2) + 3H_(2) hArr + Q) Report Delta K_(C) Value

    A
    9.3 kCal
    B
    430 kCal
    C
    220 kCal
    D
    0.293 kCal

  • AT673 K. in the formation of NH_(3) From N_(2) and H_(2) , the partial pressures of N_(2) , H_(2) and and NH_(3) at equilibrium are 0.5 , 1 and 9 xx 10^(-3) atm respectively. (N_(2) + 3H_(2) hArr + Q) Report Delta G^(@) using K_(p) value

    A
    22.66 kea
    B
    11.33 keal
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    D
    30.2 keal

  • Passage- II : AT 673 K, in the formation of NH_3 from N_2 and H_2 , the partial pressures of N_2 , H_2 and NH_3 at equilibrium are 0.5, 1 and 9 xx 10^(-3) atm respectively. ( N_2+3H_2 harr 2NH_3+Q ) Report DeltaG^(@) using K_(C) Value

    A
    9.3 kcal
    B
    430 kcal
    C
    220 kcal
    D
    0.930 kcal

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    For N_(2)+3H_(2)to2NH_(3) , rates of disappearance of N_(2) and H_(2) and rate of appearance of NH_(3) respectively are a, b and c, then

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