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The values of Kp(1) and Kp(2) for the re...

The values of `Kp_(1) and Kp_(2)` for the reaction given below are in the ratio 2: 1. If degree of dissociation of X and A are equal, then total pressure of equilibrium (1) and cquilibrium (2) are in the ratio
`X hArr Y + Z , Kp_(1) : A hArr 2B : Kp_(2) `

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Knowledge Check

  • The equilibrium constant s K_(p1) and K_(p2) for the reactions X hArr 2 Y and Z hArr P + Q respectively are in the ratio of 1 : 9 . If the degree of dissociation of X and Z be equal then the ratio of total pressures at these equilibria is

    A
    `1 : 1`
    B
    `1 : 3`
    C
    `1 :9`
    D
    `1 : 36`

  • For the reaction N_2O_4 harr 2NO_(2(g)) , the degree of dissociation at equilibrium is 0.2 at 1 atm. Then K_p will be

    A
    `1//2`
    B
    `1//4`
    C
    `1//6`
    D
    `1//8`

  • For given two equilibrium attained in a container which are correct if degree of dissociation of A and A' are alpha and alpha^(3) A_((s)) hArr 2 B_((g)) + C_((g)) , Kp_(1) = 8 xx 10^(-2) , A'_((s)) hArr 2B_((g)) + C_((g)) , K_(p_(2)) = 2 xx 10^(-2)

    A
    `(K_(p_(1)))/(K_(p_(2))) = [ ((3 alpha^(1) + 2 alpha))/((3alpha + 2 alpha^(1)) )]^(3) xx (alpha)/(alpha^(1))`
    B
    `(P^(1)C)/(P^(1)D) = 4`
    C
    `P^(1) B = 2 P^(1) C + 2P^(1) D`
    D
    ` alpha gt alpha^(1)`